«Amazing physics» 9 сыныпқа арналған
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- Results: Springs with larger spring constants will have smaller displacements than springs with lesser spring constants for the same mass added. Why
- Hooke’s Law
| equilibrium position
of each spring. Weigh the small weight on the scale and record its mass in kilograms. Why does the mass have to be in kilograms? Attach the weight to each spring one at a time, and use the ruler to measure the displacement . An easy way to do this is to measure the length of the spring, and then subtract the equilibrium length. Calculate the gravitational force exerted by the mass on the spring. F g = mg Where F g is the gravitational force, in Newtons, m is the mass of the weight, in kilograms, and g is the gravitational constant of Earth, equal to 9.81 m/s 2 . Set the gravitational force (F g ) equal to the force exerted by the spring (F). Why can you make these two variables equivalent? Use Hooke’s law to calculate the spring constant, k, for each spring. Results: Springs with larger spring constants will have smaller displacements than springs with lesser spring constants for the same mass added. Why? Hooke’s Law is a representation of linear elastic deformation. Elastic means that the spring will return to its original form once the outside force (the mass) is removed. Linear describes the relationship between the force and the displacement. The fact that the spring constant is a constant (it is a property of the spring itself), shows that the relationship is linear. Of course, Hooke’s Law only remains true when the material is elastic. If a spring is permanently deformed (by something like crushing or overstretching), it will no longer return to its original position. If you have ever played with a slinky and accidentally stretch it too far or bent it out of shape, you’ll know that it doesn’t perform like it is supposed to afterward. For Hooke’s Law to work properly, the parts of the equation have to be in the correct units. Without consistent units, the equation is meaningless. You can set the gravitational force exerted by the mass on the spring equal to the force exerted by the spring due to жүктеу/скачать 3.19 Mb. Достарыңызбен бөлісу:
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